The coefficient of static friction betweenthe m = 3.10 kg crate and the35.0° inc

ID: 1670020 • Letter: T

Question

The coefficient of static friction betweenthe m = 3.10 kg crate and the35.0° incline is 0.350. What

minimum force must be applied to the crateperpendicular to the incline to prevent the cratefrom

sliding down theincline?

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The coefficient of static friction betweenthe m = 3.10 kg crate and the35.0° incline is 0.350. What

minimum force must be applied to the crateperpendicular to the incline to prevent the cratefrom

sliding down the incline

mgsin - fs = F

==> F = mgsin -smgcos

= mg (sin - scos)

= 3.10*9.8 (0.5735 - 0.35*0.8191)

= 8.712 N

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