particle of mass5.478× 1026 kg and charge of 3.2×1019 C isaccelerated from rest

Question

particle of mass5.478× 1026 kg and

charge of 3.2×1019 C isaccelerated from rest

in the plane of the page througha potential

difference of 439 V between twoparallel plates

as shown. The particle isinjected through a

hole in the right-hand plateinto a region of

space containing a uniformmagnetic field of

magnitude 0.286 T. The particle curves ina

semicircular path and strikes adetector.

q

m

Region of

Magnetic

Field B

E

hole

What is the magnitude of theforce exerted

on the charged particle as itenters the region

of the magnetic field~B ?

Answer in units of

Explanation / Answer

         q = 3.2×1019C

       V = 439V

         B = 0.286T

Therefore

           F = B * q * ((2qV / m) )

               = 0.286 * 3.2 x 10-19 * ( 2 * 3.2 x 10-19 *439 / 5.478 x 10-26 )

               = 65. 54 x 10-16 N

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