A dipole is formed by point charges +3.4 C and -3.4C placed on the x axiz at (0.

Question

A dipole is formed by point charges +3.4 C and -3.4C placed on the x axiz at (0.45 m, 0) and (-0.45 m,0), respectively. At what positions on the x axis does the potentialhave the value 7.8 * 105 V? Express your answers using two significant figures separatedby a comma. A dipole is formed by point charges +3.4 C and -3.4C placed on the x axiz at (0.45 m, 0) and (-0.45 m,0), respectively. At what positions on the x axis does the potentialhave the value 7.8 * 105 V? Express your answers using two significant figures separatedby a comma.

Explanation / Answer

Let the point P be at (x, 0) Then distance of the point P from q = + 0.3.4 C         isd1 = x - 0.45 m Then distance of the point P from q = - 0.3.4C         isd2 = x +0.45 m Potential at P, V = V+ - V-                            = kq/d1 - kq/d2                            =kq[(1/(x-0.45) - 1/(x+0.45)]                            = kq [0.90/(x2 -0.45*0.45) Hence, (x2 -0.45*0.45) =kq*0.90/V                                = 9x109 x3.4x10-6*0.9/7.8x105          x2-0.2025   = 0.03531                  x2    = 0.23781                  x = 0.23781 = 0.4877 m The point has coordinates, (0.49,0) Then distance of the point P from q = - 0.3.4C         isd2 = x +0.45 m Potential at P, V = V+ - V-                            = kq/d1 - kq/d2                            =kq[(1/(x-0.45) - 1/(x+0.45)]                            = kq [0.90/(x2 -0.45*0.45) Hence, (x2 -0.45*0.45) =kq*0.90/V                                = 9x109 x3.4x10-6*0.9/7.8x105          x2-0.2025   = 0.03531                  x2    = 0.23781                  x = 0.23781 = 0.4877 m The point has coordinates, (0.49,0)

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