QuestionDetails: A ball swings in a vertical circle at the end of a rope 1.50 ml
ID: 1668729 • Letter: Q
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QuestionDetails: A ball swings in a vertical circle at the end of a rope 1.50 mlong attached to the ceiling. When the rope is 36.9 degrees pastthe lowest point and is on its way up, its total acceleration isgiven by (-22.5 i + 20.2 j) m/s2. At thatinstant determine the magnitude of its radial accelation and thespeed and velocity of the ball. I am confused about where to even begin. I don't reallyunderstand what they are telling me in the problem. QuestionDetails: A ball swings in a vertical circle at the end of a rope 1.50 mlong attached to the ceiling. When the rope is 36.9 degrees pastthe lowest point and is on its way up, its total acceleration isgiven by (-22.5 i + 20.2 j) m/s2. At thatinstant determine the magnitude of its radial accelation and thespeed and velocity of the ball. I am confused about where to even begin. I don't reallyunderstand what they are telling me in the problem. QuestionDetails: A ball swings in a vertical circle at the end of a rope 1.50 mlong attached to the ceiling. When the rope is 36.9 degrees pastthe lowest point and is on its way up, its total acceleration isgiven by (-22.5 i + 20.2 j) m/s2. At thatinstant determine the magnitude of its radial accelation and thespeed and velocity of the ball. I am confused about where to even begin. I don't reallyunderstand what they are telling me in the problem.Explanation / Answer
The magnitutde of total acceleration a = 30.23m/s2 The radial acceleration ar = a sin = 30.23 * sin 36.9 =18.15 m/s2 Radius R = L sin = 1.50 * sin36.9 velocity of the ball v = ar R = 18.15 * 1.50* sin36.9 = 4.043 m/s
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