Acharged particle ( q = +3.1 C) moves at speed v 0 = 49 m/s in the + x -directio

Question

Acharged particle (q = +3.1 C) moves at speedv0 = 49 m/s in the +x-direction

(east on your paper). At x = 0 it enters a region where aconstant magnetic field B

=3.2 T is directed in the +z direction (pointing out ofyour paper). (a) What is the

magnitude and direction of the magnetic force on the particle (the+y-direction

points north on your paper)? (4.86 × 10-4) Now auniform electric field is applied

sothat the net force on this particle is zero. (b) At the moment theparticle first

enters the region of the magnetic field, what direction is theforce due to the

magnetic field on the particle? (c) What are the components of theelectric field

thatbalances out this magnetic field? (156.8 N/C in whatdirection?)

Explanation / Answer

part c. the magnetic force point in +y direction, so for the netforce to be zero. The electric force have to point in -y direction.so the electric field also point in -y direction ( charge ispositive)

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