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A 8.9 resistor and a6.5 resistor are connected inseries with a power supply. (a)

ID: 1668149 • Letter: A

Question

A 8.9 resistor and a6.5 resistor are connected inseries with a power supply. (a) The voltage drop across the 6.5 resistor is measured to be10 V. Find the voltage output of thepower supply.
1 V
(b) The two resistors are connected in parallel across a powersupply, and the current through the 8.9 resistor is found to be 0.25 A. Findthe voltage setting of the power supply.
2 V
(a) The voltage drop across the 6.5 resistor is measured to be10 V. Find the voltage output of thepower supply.
1 V
(b) The two resistors are connected in parallel across a powersupply, and the current through the 8.9 resistor is found to be 0.25 A. Findthe voltage setting of the power supply.
2 V

Explanation / Answer

a) since the resistors are connected in series, their current isthe same: I6.5 = V6.5 / 6.5 = 10V/6.5= 1.54A we have: I8.9 = I6.5 = 1.54A, voltage ofthe 8.9 is: V8.9 = I8.9*8.9 = 1.54A*8.9= 13.71V the voltage output of the power supply V =V8.9 + V6.5 = 13.71V+10V = 23.71V b) when the resistors connected in parallel, their voltage arethe same V8.9 = I8.9*8.9 =0.25A*8.9 = 2.23V V6.5 = V8.9 = 2.23V the voltage setting of the power supply V = V8.9 =V6.5 = 2.23V answer: 2.23V
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