You feel your apparent weight due to normal force exerted onyour feet by the gro

Question

You feel your apparent weight due to normal force exerted onyour feet by the ground. Estimate how long should the length of theday on Earth be in order for your apparent weight when you arelocated at the equater to become zero. Radius of earth = 6.37x106m You feel your apparent weight due to normal force exerted onyour feet by the ground. Estimate how long should the length of theday on Earth be in order for your apparent weight when you arelocated at the equater to become zero. Radius of earth = 6.37x106m

Explanation / Answer

when weight becomes zero, the weight of the person gives thecentripetal acceleration , which is equal to the centripetalacceleration of one point on the quarter mg/m=2*r ; r=6.37x106m we know =2/T => T is period of the Earth(normal =1 day) => T=2/(g/r)=5065.7 s=1.4hours

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