Academic Integrity: tutoring, explanations, and feedback — we don’t complete graded work or submit on a student’s behalf.

Goodmorning A person drives a car around a circular cloverleaf with aradius of 6

ID: 1667902 • Letter: G

Question

Goodmorning A person drives a car around a circular cloverleaf with aradius of 67 m at a uniform speed of 10 m/s. a) What is the acceleration of the car?______m/s^2 b) Compare this aanswer with the acceleration due to gravityas a percentage. ________% . ( can you please explain how you gotthis answer) c) Would you be able to sense the car's acceleration if youwere riding in it? What is the force of gravity between two 1255 kg carsseparated by a distance of 30 m on _______N How does this force compare with the weight of a car? Is it larger, smaller, or roughly the same? Goodmorning A person drives a car around a circular cloverleaf with aradius of 67 m at a uniform speed of 10 m/s. a) What is the acceleration of the car?______m/s^2 b) Compare this aanswer with the acceleration due to gravityas a percentage. ________% . ( can you please explain how you gotthis answer) c) Would you be able to sense the car's acceleration if youwere riding in it? What is the force of gravity between two 1255 kg carsseparated by a distance of 30 m on _______N How does this force compare with the weight of a car? Is it larger, smaller, or roughly the same?

Explanation / Answer

Radius r= 67 m

Speed v= 10 m / s

(a). Accleration of the car a = v ^ 2/ r

                                             = 1.492 m / s^ 2

(b). Required percentage = ( a/ g ) * 100 = ( 1.492 /9.8 ) * 100

                                        = 15.229 %

©. Yes

(d). mass m = 1255 kg

Separation r= 30 m

Force of gravity F = Gm*m / r^ 2

Where G = gravitational constant = 6.67 * 10 ^ -11 N m^2 /kg^ 2

Plug the values we get F = 1.167 * 10^-7 N

Hire Me For All Your Tutoring Needs
Integrity-first tutoring: clear explanations, guidance, and feedback.
Drop an Email at
drjack9650@gmail.com
Chat Now And Get Quote