A charged metal sphere of radius 14 cm has a net charge of 6.00×10 -7 C . What i

Question

A charged metal sphere of radius 14 cmhas a net charge of 6.00×10-7C. What isthe electric field at the sphere's surface? If V = 0 at infinity, what is the electricpotential at the sphere's surface? At what distance from the sphere's surface hasthe electric potential decreased by 500 V? A charged metal sphere of radius 14 cmhas a net charge of 6.00×10-7C. What isthe electric field at the sphere's surface? If V = 0 at infinity, what is the electricpotential at the sphere's surface? At what distance from the sphere's surface hasthe electric potential decreased by 500 V?

Explanation / Answer

Given radius of the sphere r = 14 cm =14*10-2 m charge on the sphere q = 6*10-7 C    electric field on the spheresurface              E = k q / r2                 = (9*109 *   6*10-7 C /(14*10-2 )2                 =    27 .55*104 N /C       electric potential at spheresurface           V =    k q / r                 = (9*109 *   6*10-7 C /(14*10-2 )                 =    3.85*104 V                           V = 500V            V =    k q / r                 = (9*109 )*   6*10-7 C /(r            r =   (9*109*   6*10-7 C / 500                 = 10.8 m                           = (9*109 *   6*10-7 C /(14*10-2 )                 =    3.85*104 V                           V = 500V            V =    k q / r                 = (9*109 )*   6*10-7 C /(r            r =   (9*109*   6*10-7 C / 500                 = 10.8 m                           = (9*109 )*   6*10-7 C /(r            r =   (9*109*   6*10-7 C / 500                 = 10.8 m

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