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Each of the 100 identical blocks sitting on a frictionless surfaceis connected t

ID: 1667838 • Letter: E

Question

Each of the 100 identical blocks sitting on a frictionless surfaceis connected to the next block by a massless string. Thefirst block is pulled with a force of 100 N. 1) What is the tension in the string connecting block100 to block 99? 2) What is the tension in the string connecting block 50to block 51? This is confusing me. Can someone explain this problemto me?
1) What is the tension in the string connecting block100 to block 99? 2) What is the tension in the string connecting block 50to block 51? This is confusing me. Can someone explain this problemto me?

Explanation / Answer

(1)  frictionless surface the tension between block n and (n+1) is T(n) from the 2nd Law of Newton acceleration a=F/100m =T(n)/(100m -n*m) ; a is the samefor all blocks => T(n)=F*(100-n)/100 ; F=100 N n=99 => T(99)=1N (2)  the tension in the string connecting block 50to block 51 n=50 => T(50)=50N
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