Near Earth Near Earth, the density of protons inthe solar wind (a stream of part

Question

Near Earth Near Earth, the density of protons inthe solar wind (a stream of particles from the Sun) is 8.60 cm-3 and their speed is about480 km/s. (a) Find the current density of theseprotons.
1 A/m2
(b) If Earth's magnetic field did not deflect them, the protonswould strike the planet. What total current would Earth thenreceive?
2 A (a) Find the current density of theseprotons.
1 A/m2
(b) If Earth's magnetic field did not deflect them, the protonswould strike the planet. What total current would Earth thenreceive?
2 A

Explanation / Answer

   a.   Currentdensity   J   =   n* e * vd    chargeconcentration   n   =   8.60/ cm3                                           =   8.60* 106   /m3    charge onproton   e   =   1.6 *10-19   C    driftvelocity   vd   =   480   km/s                                  =   4.80* 105   m/s    J   =   8.60 *106 * 1.6 * 10-19 * 4.80 * 105          =   6.60 *10-7   A/m2          =   6.60 *10-7   A/m2    b.   Current   I   =   J* Area of earth                               =   6.60* 10-7 * 4 * Rearth2                               =   6.60* 10-7 * 4 * 3.14 * (6.40 *106)2                               =   3.39* 108   A                               =   6.60* 10-7 * 4 * 3.14 * (6.40 *106)2                               =   3.39* 108   A                               =   3.39* 108   A

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