Two point charges have a total charge equal to 215 mu C and are separated by 0.6

Question

Two point charges have a total charge equal to 215 mu C and are separated by 0.630 m. Find the charge of each particle if the particles repel each other with a force of 120 N. qi = mu C (larger charge) q2 = mu C (smaller charge) Find the force on each particle if the charge on each particle is 107.5 mu C. N

Explanation / Answer

a) F = k q1q2 / r2      ==> q1q2 =Fr2 / k = 120 * 0.630 * 0.630 / 9 x 109                      = 5.292 x 10-9 C2     Given that    q1 +q2 =215C          ..........1     Using             (q1 + q2)2 =q12 + q22 +2q1q2           ==> q12 + q22= (q1 + q2)2 -2q1q2                                               =   46225 x 10-12 - 2* 5.292 x10-9                                    = 46.225 x 10-9 - 10.584 x 10-9                                    = 35.641 x 10-9 C2               (215C - q2 )2 +q22 =   35.641 x 10-9C2                  ==> 46225 x 10-12 + q22 -2q2 * 215 x 10-6 +q22 = 35.641 x 10-9      Solve this and you get value ofq2.         Substitute the value of q2 in equation 1 and solve forq1. b) F = kq1q2 /r2 = 9 x 109 * 107.5 * 107.5 x10-12 / 0.63 * 0.63 = 262.0 N

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