A parallel-plate aircapacitor of area A = 17.3 cm 2 and plate separation of d= 3

Question

A parallel-plate aircapacitor of area A = 17.3 cm2 and plate separation of d= 3.80 mm is charged by a battery to a voltage of 60.0 V. What isthe charge on the capacitor?
hint:
What is the capacitance of a parallel plate capacitor?
If a dielectricmaterial with = 3.90 is inserted so that it fills thevolume between the plates (with the capacitor still connected tothe battery), how much additional charge will flow from the batteryonto the positive plate? What is the capacitance of a parallel plate capacitor?

Explanation / Answer

       Given           area ofthe pltes A = 17.3 cm2 =17.3*10-4m2          distance between two plates   d = 3.8 mm=3.8*10-3 m          voltage across the capaciotr   V = 60 V            o = 8.85*10-12          Capacitance of the capacitor                       C = o A    /d                           = ( 8.85*10-12 )(17.3*10-4 ) / 3.8*10-3                           = 4.029*10-12 F                             = 4.029 pF            capacitance of the capacitor with dielectric                       C1 = k( o A    / d )                             = kC   = 3.9*4.029 nF                             = 15.7131 pF           chargeon the capacitor                           Q = C1 V                              =15.7131*10-12 F *60                              = 0.942nC              plug the values and get the answers            

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