A tire is filled with air at 15ºC to a gauge pressure of220 kPa. The tire reache

Question

A tire is filled with air at 15ºC to a gauge pressure of220 kPa. The tire reaches a temperature of 38ºC. (a) What willbe the gauge pressure in the tire at 38ºC? (Answer : 2.5*10^2) (b) What fraction of the air must be removed at 38ºC torestore the original pressure of 220 kPa? ( Answer: 0.075 or 7.5%) A tire is filled with air at 15ºC to a gauge pressure of220 kPa. The tire reaches a temperature of 38ºC. (a) What willbe the gauge pressure in the tire at 38ºC? (Answer : 2.5*10^2) (b) What fraction of the air must be removed at 38ºC torestore the original pressure of 220 kPa? ( Answer: 0.075 or 7.5%) (Answer : 2.5*10^2) (b) What fraction of the air must be removed at 38ºC torestore the original pressure of 220 kPa? ( Answer: 0.075 or 7.5%)

Explanation / Answer

we use the formula PV=nRT here expansion in the volume is negligible due low coefficient of expansion of rubber hence we treat volume constant initial               final 220kPa                     ? 288K                        311K ?=237Kpa fraction of the air that has to beremoved=Tf-Ti/Ti =0.079

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