yes so two point charges are placed on thex axis. the first charge, q 1 = 8.00nC

Question

   yes so two point charges are placed on thex axis. the first charge, q1= 8.00nC, is placed adistance 16.0 m from the origin along the positive x axis; thesecond charge, q2=6.00nC, is placed a distance 9.00 mfrom the origin along the negative axis.   find theelectric field at teh origin , point 0 give the x and ycomponents of the elctric fiel as an ordered pair and expressanswer in newtons per C.    next assume that chargeq2=-6nC. what is the net electric field at theorigin, point 0? express same way

Explanation / Answer

All you need to do is find the electric field at the origin due toq_1 and add it to the electric field at the origin due to q_2. Inother words, ec{E} = ec{E}_1 + ec{E}_2

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