A.) The total current flowing through the batteryis 0.88 A. Find the value of re
ID: 1666789 • Letter: A
Question
A.) The total current flowing through the batteryis 0.88 A. Find the value of resistance R. B.)Find the current through eachresistor. C.) If the total current in the battery had beengreater than 0.88 A, would your answer to part A have beenlarger or smaller? The total current flowing through the batteryis 0.88 A. Find the value of resistance R. B.)Find the current through eachresistor. C.) If the total current in the battery had beengreater than 0.88 A, would your answer to part A have beenlarger or smaller? If the total current in the battery had beengreater than 0.88 A, would your answer to part A have beenlarger or smaller?Explanation / Answer
Given R1 = 27 R2 = 77 R3 =R voltage V = 12 V current I =0.88A The three capacitors areconnected in parallel combination 1/ R p = 1 / R1 +1/R2 +1/R3 = 1 / 27 + 1 / 77 + 1 / R 1/ Rp = 0.037 +0.012 + 1 / R = 0.0499+1/ R Rp = R / R0.0499 +1 According to ohmslaw V = I R 12 V = 0.88 ( R / R0.0499 +1) 12 (R(0.0499)+1) = 0.88 R 0.5998R+ 12 = 0.88R R = 42.82655 Current through R1 is I 1 = V / R1 = 12 / 27 = .0.4A Current through R2 is I 2 = V / R2 = 12 /77 = .0.15A Current through R3 is I 3 = V / R3 = 12 / 42.82 = .0.28 A I 3 = V / R3 = 12 / 42.82 = .0.28 A c)smaller because V = I R I = V / R I is inversly proportional to resistance .Related Questions
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