A parallel plate capacitor has a left plate with a positivecharge of +Q and a ri

Question

A parallel plate capacitor has a left plate with a positivecharge of +Q and a right plate with a charge of -Q. Themagnitude of the electric field between the plates is 100 V/m The plates each have an area of 2.0 x 10 -3 m2   with a spacing of plates of 6mm 1)Draw lines representing the equipotential lines for theelectric field between the plates 2)Calculate the charge on the left plate 3)Calculate the voltage difference between the plates 4) Calculate the energy stored in the capacitor A parallel plate capacitor has a left plate with a positivecharge of +Q and a right plate with a charge of -Q. Themagnitude of the electric field between the plates is 100 V/m The plates each have an area of 2.0 x 10 -3 m2   with a spacing of plates of 6mm 1)Draw lines representing the equipotential lines for theelectric field between the plates 2)Calculate the charge on the left plate 3)Calculate the voltage difference between the plates 4) Calculate the energy stored in the capacitor

Explanation / Answer

given that A = 2* 10-3m2 d = 6mm = 6 * 10-3m E = 100V/m potential difference between the plates V= Ed electric field between the plates E =/0                = E0 where 0=8.85*10-12C2/N.m2 charge on on one plate = Q = A capacitence = C = 0A/d plug in values C = -----F energy stored in the capacitor = E = 1/2 *C*V2 plug in values and do caliculations plug in values and do caliculations

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