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1. A golfer tees off from an elevated tee, H = 3m; the ballrises initially at an

ID: 1665884 • Letter: 1

Question

1. A golfer tees off from an elevated tee, H = 3m; the ballrises initially at an angle of elevation = 350and speed V0 = 28 m/s. How far from the tee doesthe ball strike the ground? What is the velocity if the ball(magnitude and direction) just before it lands? 2. A small projectile is shot vertically upward from a pointhing above the ground; its initial velocity is 15 m/s. What willthe velocity if the projectile when it is 20 m below tge releasepoint? How long after release will it be 20 m below the releasepoint? 1. A golfer tees off from an elevated tee, H = 3m; the ballrises initially at an angle of elevation = 350and speed V0 = 28 m/s. How far from the tee doesthe ball strike the ground? What is the velocity if the ball(magnitude and direction) just before it lands? 2. A small projectile is shot vertically upward from a pointhing above the ground; its initial velocity is 15 m/s. What willthe velocity if the projectile when it is 20 m below tge releasepoint? How long after release will it be 20 m below the releasepoint?

Explanation / Answer

1. We have two equations: y=vy*t-gt^2/2+y0 x=vx*t +x0 in this problem y0=3m, and x0=0m. vy=v*sin35 ad vx=v*cos35 plug in we have. 0=28sin35*t-9,8t^2/2+3 x=28cos35*t solve the first equation we have t=3,45s so x=79,1m 2. We have y=v*t-gt^2/2 and v-gt=v' -20=15*t-9,8t^2/2 solve we have t=4s so v=15-9,8*4=-24,2(m/s)