Four charges have the same magnitude of 2.4 *10 -12 C and are fixed to the corne

Question

Four charges have the same magnitude of 2.4 *10-12C and are fixed to the corners of a square = 4 cmon each side. 3 sides are positive and 1 is negative. Determine the magnitude of the net electric field that exists atthe center of the square. I determined the "F" but what do I do next? HELPANYONE! Four charges have the same magnitude of 2.4 *10-12C and are fixed to the corners of a square = 4 cmon each side. 3 sides are positive and 1 is negative. Determine the magnitude of the net electric field that exists atthe center of the square. I determined the "F" but what do I do next? HELPANYONE!

Explanation / Answer

Charge q = 2.4 * 10^-12 C side a = 4 cm =0.04 m electric field due to two positive charges placed on samediagonal are equal in magnitude but opposite in direction.So, theycancel each other. eletric field due to positive & negative charge placed onsame diagonal are equal in magnitude and are in samedirection. So, the magnitude of the net electric field that exists at thecenter of the square E = E ' + E " where E ' = electric field at center due to negativecharge               = Kq / r ^ 2           K =coulomb's constant = 8.99 * 10 ^ 9 N m^ 2/ C ^ 2            r= distance of the point from center = diagonal / 2             = 2 * a / 2             = a / 2            = 0.02828 m plug the values we get E ' = 26.97 N / C          E " = electric field at center due to positive charge               = Kq / r ^ 2           K =coulomb's constant = 8.99 * 10 ^ 9 N m^ 2/ C ^ 2            r= distance of the point from center = diagonal / 2             = 2 * a / 2             = a / 2            = 0.02828 m plug the values we get E " = 26.97 N / C Therefore the magnitude of the net electric field that existsat the center of the square E = E ' + E "           E =53.94 N / C               = Kq / r ^ 2           K =coulomb's constant = 8.99 * 10 ^ 9 N m^ 2/ C ^ 2            r= distance of the point from center = diagonal / 2             = 2 * a / 2             = a / 2            = 0.02828 m plug the values we get E " = 26.97 N / C Therefore the magnitude of the net electric field that existsat the center of the square E = E ' + E "           E =53.94 N / C

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