A set of point charges is held in place atthe vertices of an equilateral triangl

Question

A set of point charges is held in place atthe vertices of an equilateral triangle of side 10.0 cm, asshown in the figure (a) . Find the maximum amount of total kineticenergy that will be produced when the charges are released fromrest in the frictionless void of outer space. I got this portion correctby solving with KE=k*((q1*q2)+(q2*q3)+(q1*q3))/.1 Repeat part A if the charges are initially at the vertices ofthe right triangle shown in the figure (b). How does that formula change to get partB? Repeat part A if the charges are initially at the vertices ofthe right triangle shown in the figure (b). How does that formula change to get partB?

Explanation / Answer

You are almost there. Just add up the interactionsbetween each particle separately KE = k (q1q2)/r12 + q2q3/r23 + q1q3/r13) r12 = 10 cm r23 = 15 cm r13 = [(10cm)^2 + (15cm)^2] = 513 cm ~ 18.03cm . KE = 1.68 J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.