NOTE: The back of the book for this questions lists the answers below which are

Question

NOTE: The back of the book for this questions lists the answers below which are correct. I would like to know how they got these solutions with work shown and steps. 1 A) .6 (B) .4 (C) Yes (D) 0 (E) 1

1. A pair of codominant alleles governs coat color in shorthorn cattle: CRCR is roan, CRCW is roan (red and white), and CWCW is white. A sample of cattle population revealed the following phenotypes: 180 red, 240 roan, and 80 white. (A) what is the frequency of the CR allele? (B) What is the frequency of the CW allele? (C) Does this sample indicate that the population is in equilibrium? (D) what is the chi square value? (E) How many degrees of freedom exist in this question?

Explanation / Answer

Answer:

A). 0.6

CRCR is Red, CRCW is roan (red and white), and CWCW is white

The frequency of Red (CRCR) phenotype = 180/500 = 0.36

The frequency of red allele (CR) = Sqrt of 0.36 - 0.6

B). 0.4

The frequency of White (CWCW) phenotype = 80/500 = 0.16

The frequency of white allele (CW) = Sqrt of 0.36 - 0.4

Roan frequency = 240/500 = 0.48

C). Yes the population is in equilibrium

Equilibrium population consists of p + q = 1

Where p is the frequency of one allele and q is the frequency of the other allele.

0.36 + 0.16+ 0.48 = 1

D). Chi-Squre value = 40.80

E). The degrees of freedom = 2

Degrees of freedom = number of phenotypes - 1

= 3-1 = 2

Phenotype Observed(O) Expected (E) O-E (O-E)2 (O-E)2/E Red 180 125 55 3025.00 24.20 Roan 240 250 -10 100.00 0.40 White 80 125 -45 2025.00 16.20 500 500 40.80

Related Questions

Navigate

• Browse (All)
• Browse N
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.