A bicyclist makes a trip that consists of three parts, each in thesame direction

Question

A bicyclist makes a trip that consists of three parts, each in thesame direction (due north) along a straight road. During the firstpart, she rides for 22 minutes at an average speed of 6.8 m/s. During the second part, she rides for 36minutes at an average speed of 11.6m/s. Finally, during the third part, she rides for 8 minutes at anaverage speed of 7.3 m/s. (a) How far has the bicyclist traveled duringthe entire trip?
1 m

(b) What is her average velocity for the trip?
2 m/s due north
(a) How far has the bicyclist traveled duringthe entire trip?
1 m

(b) What is her average velocity for the trip?
2 m/s due north

Explanation / Answer

For each part, you need to find the distance d = v*t a) 1320sec * 6.8m/s = 8976m b) 2160sec * 11.6m/s = 25056m c) 480sec * 7.3m/s = 3504m Add them all up 37536m Average velocity is total distance/total time 37536m/3960s = 9.49m/s Hope that helps

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