A skateboarder, starting from rest, rolls down a 15.0 m ramp. When she arrives a

Question

A skateboarder, starting from rest, rolls down a 15.0 m ramp. When she arrives at the bottom of theramp her speed is 7.10 m/s. (a) Determine the magnitude of heracceleration, assumed to be constant.
1___________ m/s2

(b) If the ramp is inclined at 22.0°with respect to the ground, what is the component of heracceleration that is parallel to the ground?
2___________ m/s2

A quarterback claims that he can throw the football ahorizontal distance of 196.6 m (215 yd).Furthermore, he claims that he can do this by launching the ball atthe relatively low angle of 25° above the horizontal. To evaluate his claim,determine the speed with which this quarterback must throw theball. Assume that the ball is launched and caught at the samevertical level and that air resistance can be ignored. Forcomparison, a baseball pitcher who can accurately throw a fastballat 45 m/s (100 mph) would be considered exceptional.
1___________ m/s


(a) Determine the magnitude of heracceleration, assumed to be constant.
1___________ m/s2

(b) If the ramp is inclined at 22.0°with respect to the ground, what is the component of heracceleration that is parallel to the ground?
2___________ m/s2

A quarterback claims that he can throw the football ahorizontal distance of 196.6 m (215 yd).Furthermore, he claims that he can do this by launching the ball atthe relatively low angle of 25° above the horizontal. To evaluate his claim,determine the speed with which this quarterback must throw theball. Assume that the ball is launched and caught at the samevertical level and that air resistance can be ignored. Forcomparison, a baseball pitcher who can accurately throw a fastballat 45 m/s (100 mph) would be considered exceptional.
1___________ m/s

Explanation / Answer

15 = 1/2 *a*t^2 a*t = 7.1 t= 7.1/a ==> 30 = 7.1^2/a a1 = 7.1^2/30 cos(22) * a1   = ax            :where a1 was the acceleration found in part A and ax is the xcomponent of                                           acceleration. for part c: 196.6 = cos(25)*v *t t = v*cos(25)/196.6 0 = v*sin(25)*v*cos(25)/196.6 - 1/2*9.8*(v*cos(25)/196.6)^2 solve for v.

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