A charge of -3.45 nC and a chargeof -6.65 nC are separated by adistance of 30.0

Question

A charge of -3.45 nC and a chargeof -6.65 nC are separated by adistance of 30.0 cm. Find the positionat which a third charge of +7.70 nCcan be placed so that the net electrostatic force on it iszero.
cm from the -3.45 nC charge
cm from the -6.65 nC charge

Please any help would be very appreciated! A charge of -3.45 nC and a chargeof -6.65 nC are separated by adistance of 30.0 cm. Find the positionat which a third charge of +7.70 nCcan be placed so that the net electrostatic force on it iszero.
cm from the -3.45 nC charge
cm from the -6.65 nC charge

Please any help would be very appreciated!

Explanation / Answer

Given q = -3.45 * 10 ^ -9 C            q' = -6.65 * 10 ^ -9 C            Q= 7.7 * 10 ^ -9 C separation of the charges r = 30 cm = 0.3 m Let at a distance x from the charge q , net electric field iszero. Force on Q due to q = Force on Q due to charge q ' KQq / x ^ 2 = K Q q ' / ( r-x ) ^ 2 [(r-x) / x ] ^ 2 = q ' / q ( r-x ) / x = [ q ' / q ]                = 1.388       r-x = 1.388 x           r =2.388 x           x = r /2.388             = 0.1256 m = 12.56 m Distance from charge -3.45 nC is = 12.56 cm Distance of the point from charge -6.65 nC is = 30 cm - 12.56cm                                                                      =17.44 cm

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