a) Assuming a resistivity of 1 x 10 13 m,calculate the resistance between the en

Question

a) Assuming a resistivity of 1 x 1013 m,calculate the resistance between the ends of a rubber band that is18 cm long and 1.6 mm in diameter. the answer was 8.95 E17. b) calculate the resistance between the "heads" and "tails"sides of a penny that is 1mm thick and 2 cm in diameter. (answer in ) c) what is the expected current that each would carry if itwere connected across a 116 V power supply? (Do not try this athome!) rubber band (Amperes) penny (Amperes) a) Assuming a resistivity of 1 x 1013 m,calculate the resistance between the ends of a rubber band that is18 cm long and 1.6 mm in diameter. the answer was 8.95 E17. b) calculate the resistance between the "heads" and "tails"sides of a penny that is 1mm thick and 2 cm in diameter. (answer in ) c) what is the expected current that each would carry if itwere connected across a 116 V power supply? (Do not try this athome!) rubber band (Amperes) penny (Amperes)

Explanation / Answer

R = L / A = 1 * 10E13 * .18 / ( *.0082) = 8.95 * 10E17 For the penny: R = * .001 / ( * .012) = 10 /        Substitute theresistivity of copper (), substitute and solve I = 116 / R       substitute thevalues of R found above to obtain the currents

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