Run Mass of cart(kg) m 2 Total mass (kg) m 1 +m 2 Acceleration calculated from t
ID: 1663002 • Letter: R
Question
Run
Mass of cart(kg)
m2
Total mass (kg)
m1+m2
Acceleration calculated from theory (m/s2)
Acceleration measured from run (m/s2)
Percentage Error
% difference
# 1
.277
.292
.503
.48
4%
# 2
.2
.312
.47
.44
6.38%
# 3
.367
.372
.39
.37
5.1%
# 4
.257
.272
.5
.48
4.%
Post-LabConclusions:
1. For runs # 2,3 and 4 in part-A, what did you notice about the slope of thelinear fit as the net force remained constant but the total mass isincreased?
2. What happensto an object’s acceleration if the net force applied to theobject is kept constant but the object’s massincreases?
3. Why did theslope of velocity versus time change for each run inpart-B?
4. For the runson the part-B, what did you notice about the slope of the linearfit as the net force is increased while the mass is keptconstant?
5. What happensto an object’s acceleration if the net force applied to theobject is increased but the object’s mass is keptconstant?
Run
Mass of cart(kg)
m2
Total mass (kg)
m1+m2
Acceleration calculated from theory (m/s2)
Acceleration measured from run (m/s2)
Percentage Error
% difference
# 1
.277
.292
.503
.48
4%
# 2
.2
.312
.47
.44
6.38%
# 3
.367
.372
.39
.37
5.1%
# 4
.257
.272
.5
.48
4.%
Explanation / Answer
Post-LabConclusions:
1. For runs # 2,3 and 4 in part-A, what did you notice about the slope of thelinear fit as the net force remained constant but the total mass isincreased?
The slope isthe value of the inverse of the mass multiplied by the forceapplied.
2. What happensto an object’s acceleration if the net force applied to theobject is kept constant but the object’s massincreases?
3. Why did theslope of velocity versus time change for each run inpart-B?
Because theacceleration kept changing. Acceleration is the derivative ofvelocity with respect to time, so acceleration is the slope of thevelocity versus time graph.
4. For the runson the part-B, what did you notice about the slope of the linearfit as the net force is increased while the mass is keptconstant?
The slope isthe value of the mass. Just like a linear equation: y = mx + b. Inour case, b = 0, y = F, m = m, x = a: F = ma.
5. What happensto an object’s acceleration if the net force applied to theobject is increased but the object’s mass is keptconstant?
F = ma => a = F / m. So,force is directly proportional to acceleration. As force increases,acceleration increases.
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