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This is suppose to be an easy question, but i just can\'t getit. I need help ton

ID: 1662968 • Letter: T

Question

This is suppose to be an easy question, but i just can't getit. I need help tonight!!! It is problem 20 from chapter 16. The lowest frequency in the audible range is 20 Hz. What isthe length of the shortest open-open tube? What is the shortestopen-closed tube needed to produce this frequency? Any help is appreciated! This is suppose to be an easy question, but i just can't getit. I need help tonight!!! It is problem 20 from chapter 16. The lowest frequency in the audible range is 20 Hz. What isthe length of the shortest open-open tube? What is the shortestopen-closed tube needed to produce this frequency? Any help is appreciated!

Explanation / Answer

from f = v = 343/20 = 17.15 m for open-open tube, shortest length L is given by = 2L L = 8.575 m for open-closed tube, shortest length L is given by = 4L L = 4.2875 m

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