The work function for titanium is4.33 eV. (a) Convert the value of the workfunct

Question

The work function for titanium is4.33 eV. (a) Convert the value of the workfunction from electron volts to joules.
Enter anumber. 1 J

(b) Find the cutoff frequency for titanium.
Enter anumber. 2 Hz

(c) What maximum wavelength of light incident on titanium releases photoelectrons from the titanium's surface?
Enter anumber. 3 m

(d) If light of energy 7.2 eV is incidenton titanium, what is the maximum kineticenergy of the ejected photoelectrons? Give the answer in electronvolts.
Enter anumber. 4 eV

(e) For photons of energy 7.2 eV, whatstopping potential would be required to arrest the current ofphotoelectrons? Enter anumber. Enter anumber. Enter anumber. Enter anumber.

Explanation / Answer

a) 4.33eV=4.33*1.6*10-19=6.928*10-19J. b) for cutoff frequency: hf=w; f=6.928*10-19/6.626*10-34=1.045*1015Hz. c) for minimum wavelength: hc/=w; =6.626*10-34*3*109/6.928*10-19=2.86*10-6m. d) K.Emax=7.2-4.33=2.87eV. e) energy = charge *potential difference. e.V=2.87eV. V=2.87V.

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