Three charger are located on a. horizontal axis. Let up 1x the positive directio

Question

Three charger are located on a. horizontal axis. Let up 1x the positive direction. The Coulomb constant is 8.98755 times 109 N m2 /C2. Determine the magnitude of the electric field m p. vertically above the charge -0.81 /rC as shown in the figure. above. Answer in units of V/m. 009 (part 2 of 3 10. 0 points Calculate the magnitude of the vertical component of the electric force on n -3.5 pC charge placed at point p. Answer in units of N. 010 (part 3 of 3) 10.0 points The force is in the downward direction. is in the upward direction. is in the right-hand direction. is zero in magnitude and its direction is undefined. is in the left-hand direction.

Explanation / Answer

.    Vertical component of force on P due to - 0.84 *10-6  C is : .    F1 = k ( - 0.84 * 10-6  C * - 3.5 * 10-6  C ) / (1.5924)2   .       = 0.01043 N .       Vertical component of force on P due to right 12 * 10-6  C is : .    F2 = { k ( 12 * 10-6  C * - 3.5  * 10-6  C ) / [(1.5924)2  + (2.5)2 ] } *sin45 .       =   { k ( 12 *10-6  C * - 3.5  *10-6  C ) / 8.786 } *sin45 .       = - 0.03042 N .    Similalry .         Vertical component of force on Pdue to right 12 * 10-6  C is: .    F3 = { k ( 12 * 10-6  C * - 3.5  * 10-6  C ) / [(1.5924)2  + (2.5)2 ] } *sin45 .       =   { k ( 12 *10-6  C * - 3.5  *10-6  C ) / 8.786 } *sin45 .       = - 0.03042 N . Hence total vertical component of force is : .    F1 + F2 + F3 = ------------- N . hpe this helps u!

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