1) A spaceship of triangular shape, having a length twice itswidth, is capable o
ID: 1662306 • Letter: 1
Question
1) A spaceship of triangular shape, having a length twice itswidth, is capable of relativistic speeds. How fast would ithave to move so that to a stationary observer its length wouldequal its width?
a. 0.500 c b. 0.750 c c. 0.866 c d.This is not possible.
2) At whatspeed must an object be moving in order that it has a kineticenergy 1.50 times its rest energy? (c = 3.00 ´108 m/s)
a. 1.91 ´ 108m/s b. 2.52 ´ 108 m/s c.2.75 ´ 108 m/s d. 2.90 ´108 m/s
3) An electronand a positron both of rest energy 0.511 MeV slowly drift togetherand annihilate into two gamma ray photons. What is the wavelengthof each of the photons? (h = 6.63 ´10-34 J×s, c = 3.00 ´108 m/s, and 1 eV = 1.60 ´10-19 J)
a. 1.21 ´10-12 m b. 2.43 ´10-12 m c. 4.86 ´10-12 m d. 9.72 ´10-12 m
4) A proton (mass = 1.67 ´10-27 kg) has a kinetic energy of 1.00 MeV.If its momentum is measured with an uncertainty of 1.00%, what isthe minimum uncertainty in its position? (h = 6.63 ´10-34 J×s, 1 eV = 1.6 ´10-19 J)
a. 9.08´ 10-13 m b. 2.28 ´10-13 m c. 9.08 ´10-14 m d. 5.64 ´10-14 m
Explanation / Answer
We know the formula the proper length is L = Lo[1 - (v2 / c2)] L= 2L[1 - (v2 / c2)] 1 / 2 = [1 - (v2 / c2)] [1- (v2 / c2)] = 1 / 4 v2 / c2 = 3/4 v = (3/4) c = 0.866cRelated Questions
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