The work function for indium is4.12 eV. (a) Convert the value of the work functi

Question

The work function for indium is4.12 eV. (a) Convert the value of the work function fromelectron volts to joules.
J

(b) Find the cutoff frequency for indium.
Hz

(c) What maximum wavelength of light incident on indium releases photoelectrons from the indium's surface?
m

(d) If light of energy 7.4 eV is incidenton indium, what is the maximum kineticenergy of the ejected photoelectrons? Give the answer in electronvolts.
eV

(e) For photons of energy 7.4 eV, whatstopping potential would be required to arrest the current ofphotoelectrons?
V (a) Convert the value of the work function fromelectron volts to joules.
J

(b) Find the cutoff frequency for indium.
Hz

(c) What maximum wavelength of light incident on indium releases photoelectrons from the indium's surface?
m

(d) If light of energy 7.4 eV is incidenton indium, what is the maximum kineticenergy of the ejected photoelectrons? Give the answer in electronvolts.
eV

(e) For photons of energy 7.4 eV, whatstopping potential would be required to arrest the current ofphotoelectrons?
V J

(b) Find the cutoff frequency for indium.
Hz

(c) What maximum wavelength of light incident on indium releases photoelectrons from the indium's surface?
eV

(e) For photons of energy 7.4 eV, whatstopping potential would be required to arrest the current ofphotoelectrons?
V

Explanation / Answer

Work function W = 4.12 eV

(a). W = 4.12 eV = 4.12 * 1.6* 10 ^ -19 J

          = 6.592 *10 ^ -19 J

(b). Cut off frequency f = W / h

Where h = planck’s constant = 6.625 * 10 ^ -34J s

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