10. You push a wheelbarrow a distance of 60.0 m at a constant speed for 25.0 s,

Question

10. You push a wheelbarrow a distance of 60.0 m at a constant speed for 25.0 s, by exertin a 145-N force horizontally a. What power do you develop? b. If you move the wheelbarrow twice as fast, how much power is developed? 11. What power does a pump develop to lift 35 L of water per minute from 12. An electric motor develops 65 KW of power as it lifts a loaded 13. A winch designed to be mounted on a truck, as shown in a depth of 110 m? (1 L of water has a mass of 1.00 kg.) elevator 17.5 m in 35 s. How much force does the motor exert? Figure 10-7, is advertised as being able to exert a 6.8×103-N force and to develop a power of 0.30 kW. How long would it take the truck and the winch to pull an object 15 m? r has stalled and you need to push it. You notice as the car for the first 15 m. your force decreased at a constant rate from to 40.0 N. How much work did you do on the car? Drawa 14. Your ca gets going that you need less and less force to keep it going. S that uppose displacement graph to represent the work done during this period. Chapter 10 Energy, Work, and Simple Machines

Explanation / Answer

power = force * velocity

= force * distance/time

= 145*60/25

= 348 watt

if speed is doubled then power will also double.

so power in second case is 348*2 = 696 watt

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