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o T-Mobile Wi-Fi 8:09 PM session.masteringphysics.com C e Ch 21 HW Problem 2187

ID: 1661862 • Letter: O

Question

o T-Mobile Wi-Fi 8:09 PM session.masteringphysics.com C e Ch 21 HW Problem 2187 Two 1.20m nonconducting wires meet at a right angle. One segment carries 4 00 C of charge distributed uniformly along its length, and the other carries-4.00 C distributed uniformly along it, as shown in the figure 1.20m Part A Find the magnitude of the electric field these wires produce at point P, which is 60.0 cm from each wire. N/c Request Answer Part B Find the direction of the electric field these wires produce at point P. which is 60.0 cm from each wire. (Suppose that the y-axis directed vertically) Request Answer -Part C If an electron is released at P, what is the magnitude of the net force that these wires exert on it? Request Answer Part D

Explanation / Answer

Each wire produces an electric field at P due to a finite wire

the magnitude of electric field is

E = kQ/ x sqrt x^2 + a^2

the fild due to negative wire points to the left and positive wire points doward . these two directions perpendicular to each other and of equal magnitude. the net filed is the vector sum of thesetwo fileds

E net = 2E1 cos 45

= 2kQ/ xsqrt x^2 + a^2 * cos 45

= 2( 9* 10^9) (4* 10^-6) cos 45/0.6 sqrt (0.6)^2 + 0.6^2

=10.0* 10^4 N/C

(b)

the direction is (90+45 = 135 degree) counterclockwise from an y axis

(c)

The relation between force and charge is

F = eE = 1.6 * 10^-19 ( 10.0* 10^4) = 1.6 * 10^-14 N

(d)

the direction of force is opposite to the direction of the electric
field, since the electron has negative charge.

that is 225-180 = 45 degree