g. × C) Lab 01: Lesson . R The Expert TAh X × New Tab Files . OneDrive × + https
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g. × C) Lab 01: Lesson . R The Expert TAh X × New Tab Files . OneDrive × + https://use11fltheexpertta.comCc 80% Home 1 Studen maeganjnut.edu My Account Log Out Help IHW 1 Begin Date: 1/8/2018 12:01:00 AM-Due D Date: 1/22/2018 100000 PM End Date: 122/2018 10:00:00 PM (8%) Problen 1: A 53 g ball of copper has a net charge of 2.25 pC What fraction of the copper's electrons has been removed? Each copper atom has 29 protons, and copper has an atomic mass of 63.5 Grade Seanary Poletal 95% Anemps resaining eotan acos atan) acctan) sinh cosh) cotan Degrees O Radians Sabmit I give u Hiati: 1% dedu toopcr hat Hints remaning: Fredbace1% doducto per feedbackExplanation / Answer
1)
Number of electrons normally present,
(53/63.5)mol x 6.022 x 10^23(atoms per mol) x 29(electrons per atom) = 1.46 x 10^25 electrons
Electrons removed = n
ne = 2.25 x 10^-6C
n = 2.25 x 10^-6C / 1.60 x 10^-19C/e
n = 1.40 x 10^13 electrons removed
Fraction removed = 1.40 x 10^13 removed / 1.46 x 10^25 normally
= 0.95 x 10^-12 = 1 x 10^-12 (approx)
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