Question NoT: Ce sinusoidal electromagnetic wave having magnetic field of amplit
ID: 1661246 • Letter: Q
Question
Question NoT: Ce sinusoidal electromagnetic wave having magnetic field of amplitude B 1.25uT speed of light(e).(3+3+4+3+3- 16 points) and a wawlength of -432nm is traveling in the + x direction with (a) What is the frequency 1) of this wave? (b) What is the amplituc (c) Write the wave equations for the electric and magnetic fields as a funce- tions of a and t (hint: Look at wave equation in formula sheet r,) be E(r.t) or B(x,t).) (d) Calculate average energy (uar) of the beam (e) Calculate the intensity(Sar) of the beamExplanation / Answer
a) For any Electromagnetic wave, Frequency f, wavelength are related by :
Speed of light, c = f *
In our question, = 432 nm = 432 * 10-9 m
c = 3* 108 m/s
Hence, Frequency, f = c/ = 3* 108 m/s/ 432 * 10-9 m = 6.355 * 1014 s-1 or 6.355 * 1014 Hz
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