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1. You are arguing over a cell phone while trailing an unmarked police car by 31

ID: 1661113 • Letter: 1

Question

1. You are arguing over a cell phone while trailing an unmarked police car by 31 m. Both your car and the police car are traveling at 100 km/h. Your argument diverts your attention from the police car for 2.0 s (long enough for you to look at the phone and yell, "I won't do that!"). At the beginning of that 2.0 s, the police officer begins emergency braking at 5 m/s2.

(a) What is the separation between the two cars when your attention finally returns? (Hint: This problem might be a bit easier to solve using the idea of relative velocity.)
_____ m
(b) Suppose it takes you another 0.4 s to realize your danger and begin braking. If you too brake at 5 m/s2, what is your speed when you hit the police car?
______ km/h
(c) How much time passes between your initial braking and the collision?
_______s
(d) How much distance do you cover during this time (i.e., while braking)?
_____m


2. You are to drive to an interview in another town, at a distance of 340 km on an expressway. The interview is at 11:15 A.M. You plan to drive at around 100 km/h, so you leave at 8:00 A.M. to allow some extra time. You drive at that speed for the first 100 km, but then construction work forces you to slow to 45 km/h for 40 km. What would be the least speed needed for the rest of the trip to arrive in time for the interview?

______km/h

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Explanation / Answer

2.

Total time = 11:15 AM - 8:00 AM = 3 hr 15 min

time needed at speed of 100 km/hr

t1 = 100/100 = 1 hr

time needed at speed of 45 km/hr

t2 = 40/45 = 0.89 hr

Time remaining = 3.25 hr - 1 hr - 0.89 hr = 1.36 hr

distnace remaining = 340 - 100 - 40 = 200 km

So speed for this distance should be

V = 200/1.36 = 147.05 km/hr