18. ladd radiolabelled Glyceraldehyde 3-Phosphate (GA-3-P) to wildtype and mutan

Question

18. ladd radiolabelled Glyceraldehyde 3-Phosphate (GA-3-P) to wildtype and mutant cells and follow the radiolabel over time. My data is shown below (white rows are WT, and shaded rows are MUTANT). What is the BEST, COMPLETE explanation for these results? Radiolabeled metabolite (Hmolar) Time (mins) GA-8-P 1,8 bisphosphoglycerate Glucose-6-PO Glucose 70 70 10 75 10 00 120 00 mutant strain lacks the enzyme to do Glucose-phosphate 15. lam studying a newly discovered virus. I find that the virus causes infected cells to die. I now take cells, or cells treated with the enzyme glycosidase, expose them to the virus and after 3 days, measure the number of live cells present. My data is shown. What is the BEST, COMPLETE biochemical explanation for these observations? Glycosidase fewere cells living in the glycosidate-treated cells 17. I am attempting to create the Glycolytic pathway (Glc- Pyruvate) in vitro. I purify all the enzymes of the pathway, the co-factors required, NAD+ and ATP.lthen mix all these components together and add Glucose. I then measure the ratio of Pyruvate:Glucose in the mixture over time. My data is shown in the graph. At the point marked "X" in the graph, E l added an additional purified protein (that is not a component of the Glycolytic pathway. Time MOST LIKELY what protein didiadd? Explain your answer. no idea 19. A certain protein, "X" is normally found in the lysosome. I make two versions of Xin vitro. One is glycosylated with Mannose-6-PO4 and the other is not. introduce these two versions of X into the cytoplasm of cells, and follow their localization within the cell. MOSTLIKELY predict where the two versions will end up in the cell. Explain. glysocgenated protein will bind to mannose-6-phophat e receptor

Explanation / Answer

13. According to the given data, it is following gluconeogenesis pathway. This is the reason why we didn't observe radioactivity in 1,3-bisphosphoglycerate and observed radioactivity is present in glucose of wild type cells. But there is no radioactivity present in the glucose of mutated cells because mutation present in the glucose-6-phosphatase, the enzyme which converts glucose-6-phosphatase into glucose.

15. Yes, you are correct. In the presence of glycosidase, the number of living cells is less the non treated cells.

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