b. in seconds how long did the trip take? c. how long in minutes? d. how much di
ID: 1660354 • Letter: B
Question
b. in seconds how long did the trip take?
c. how long in minutes?
d. how much distance in kilometers traveled for whole trip?
what is the magnitude of Steve's displacement?
E. what is the direction of Steve's displacement for the entire trip?
Explanation / Answer
Average velocity is 2V1 V2 / v1+v2 = 2*6.1*2.4/8.5 = =3.44m/s
b.) t = s/v = 2*1900/3.44 = 2*552.32s = 1104.64s
c) 1104.64s = 1104.64/60 = 18.41mints
d.) Total distance travelled by him is 1900+1900 = 3800m = 3.8km. Displacement is a vector quantity, hence it becomes zero for any round trip.
But magnitude of any non continues trip is square root of magnitude of out going distance + magnitude of in coming distance = 1.92 km.
e.) No direction.
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