+ 43.2 m/s -43.2 m/s QUESTION 9 Train A is moving east with a speed of 13 m/s wi

Question

+ 43.2 m/s -43.2 m/s QUESTION 9 Train A is moving east with a speed of 13 m/s with respect of train B, and train B is traveling north with a speed of 28 m/s with respect of ground. What is the velocity (magnitude and direction) of train A with respect of ground (VAG)? (tip: this is a 2D-problem but can be solved using perpendicular vectors and you have Ground (G), Train A and Train B) 31 mis , 650 NE 31 mis , 250 NE 41 mis , 650 N-E 41 m/s , 250 NE Click Save and Submit to save and submit. Click Save AllL Ansuers to save all ansuers Save All Answers

Explanation / Answer

Given ,

Va/b = 13i ( velocity of A with respect to B in the East )

Vb/g = 28j ( velocity of B with respect to ground)

Here i and j are the unit vectors along x axis and y axis

Now , velocity of A with respect to ground (Va/g) is :

Va/g = Va/b + Vb/g

Va/g = 13i + 28j

Magnitude of Va/g = (13^2 + (28)^2) = 31 m/s

Direction : = tan^-1(28/13) = 65°( N of E)

Therefore, answer) option A) 31 m/s , 65° N of E

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