The swimmer shown in Figure 6.24 exerts an average horizontal backwarod force of

Question

The swimmer shown in Figure 6.24 exerts an average horizontal backwarod force of 70.0 N with his arm during each 1.80 m long stroke. 1.8 Figure 6.24 (a) What is his work output in each stroke? (b) Calculate the power output of his arms if he does 100 strokes per minute. 14. -1 points OSColPhys1 14.P005 WA My Notes Ask Your Teach Rubbing your hands together warms them by converting work into thermal energy. If a woman rubs her hands back and forth for a total of 29 rubs a distance of 7.50 cm each and with a frictional force averaging 51.3 N, what is the temperature increase? The mass of tissue warmed is only 0.100 kg, mostly in the palms and fingers. The specific heat of the tissue is 3500 J/(kg °C) oc Supporting Materials Physical Constants

Explanation / Answer

13)(a) Work is given by, W = F*s = 70*1.8 = 126 J

(b) power = total work / time = 126*100/60

= 210 W

14) Work = 29*Fs = 29*51.3*0.075

m S deltaT = 29*51.3*0.075

delta T = 29*51.3*0.075 /(0.100*3500)

= 0.32 °C

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