To better understand the concept of static equilibrium a laboratory before perfo

Question

To better understand the concept of static equilibrium a laboratory before performing the experiment. The apparatus consists of a round level table in the center of which is a massless ring. There are three stri e asks the student to make a calculation tied to different spots on the ring. Each string asses parallel over the table and is individually strung over a onless pulley (there are three pulleys) where a mass is hung The table is degree marked to indicate the position or angle of each string. There is a mass m 157 g located at , 24.5 and a second mass m2-227 g located at 2-291. Calculate the mass ms, and location (in degrees) , which will balance the system and the ring will remain stationary Number 3. Number

Explanation / Answer

Lets find force due to first to masses.

F1=m1g =0.157g

F2 = 0.227g

Now Resultant of this force, R = sqrt(0.157^2 +0.227^2 +2*0.157*0.227* cos (291 - 24.5) degree)

= sqrt(0.157^2 +0.227^2 +2*0.157*0.227* cos 266.5 degree)  *g

  = 0.268*g

Hence m3 = 268 g

Let it be at angle theta,

268*cos theta +157 cos 24.5 degree + 227 cos 291 degree =0

cos theta =- (157 cos 24.5 degree+227cos 291 degree) /268

= - 0.8366

theta = 146.8 degree

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