Blacks A, B, and C are placed as in the figure and connected by ropes of negligi

Question

Blacks A, B, and C are placed as in the figure and connected by ropes of negligible mass. both A and B weigh 30.0N

Just part E I cannot figure out, already input 5.99 and -5.9 and those were wrong

What is the weight of block C? Blocks A, B, and C are placed as in the figure(Figure 1) and connected by ropes of negligible mass. Both A and B weigh 30.0 N each, and the coefficient of kinetic friction between each block and the surface is 0.39. Block C descends with constant velocity toc= 39.1 N Submit My Answers Give Up Correct s Feedback: Your answer 39.0689 N was either r different number of significant figures than required for this part If you need this result for any later calculation in this item, keep all the digits and round as the final step before submitting your answer Figure 1 of! Part E f the rope connecting A and B were cut what would be the acceleration of C? acceleration of C? az Submit Mv Answers Give tlp 36.99 Incorrect: Try Again; 4 attempts remaining IMG 6529.JPG 0 Type here to search

Explanation / Answer

perpendicular to incline force equation is given as

Fn = mB g Sin36.9

kinetic frictional force is given as

f = uk Fn = (0.39) mB g Sin36.9

parallel to incline , force equation is given as

T - f - mB g Sin36.9 = mB a

T - (0.39) mB g Sin36.9 - mB g Sin36.9 = mB a eq-1

for block C , force equation is given as

mc g - T = mc a

T = mc g - mc a

using eq-1

mc g - mc a - (0.39) mB g Sin36.9 - mB g Sin36.9 = mB a

mc g - (0.39) mB g Sin36.9 - mB g Sin36.9 = (mc + mB)a

a = (mc g - (0.39) mB g Sin36.9 - mB g Sin36.9) /(mc + mB)

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