-) cl Secure I https//usp2rStreepettacnmCommervTakeTuiruuasimentas End Date: 1 H
ID: 1659248 • Letter: #
Question
Explanation / Answer
consider the motion as the ball comes down
Vo = initial velocity at Top = 0 m/s
Vf = final velocity just before hitting the surface = ?
a = acceleration = - 9.8
Yo = initial position = 1.75 m
Y = final position = 0 m
using the equation
Vf2 = Vo2 + 2 a (Y - Yo)
Vf2 = 02 + 2 (- 9.8) (0 - 1.75)
Vf = 5.86 m/s
b)
Consider the motion while going up
Vo = initial velocity
Vf = final velocity at the top = 0 m/s
Y = displacement = 1.325 m
using the equation
Vf2 = Vo2 + 2 a Y
02 = Vo2 + 2 (- 9.8) (1.325)
Vo = 5.1 m/s
t = 8 x 10-5 sec
Vo = initial velocity = - 5.86 m/s
Vf = final velocity = 5.1 m/s
using the equation
a = (Vf - Vo)/t = (5.1 - (- 5.86))/(8 x 10-5 ) = 1.37 x 105 m/s2
Related Questions
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.