1. Question Details Q4 P1 [4006861] - A climber whose mass is 53 kg hangs from a
ID: 1659091 • Letter: 1
Question
1. Question Details Q4 P1 [4006861] - A climber whose mass is 53 kg hangs from a rope 11 m below a ledge. What is the magnitude of the tension in the rope? tension Later, his friend pulls him up with a constantly increasing speed that is initially 0 m/s when he is at the bottom and 5 m/s when he reaches the ledge. It takes 70 s to pull him up. What is the y-component of the rate of change of momentum of the dt Now what is the magnitude of the tension in the rope while he is being pulled up? tension-Explanation / Answer
here,
mass , m = 53 kg
length , l= 11 m
a)
the tension in the rope , T = m * g
T = 519.9 N
b)
time taken , t = 70 s
final speed , v = 5 m/s
let the accelration be a
v = u + a * t
5 = 0 + a * 70
solving for a
a = 0.071 m/s^2
the rate of change of momentum = m * a = 53 * 0.071 = 3.79 kg.m/s^2
c)
let the magnitude of tension in the rope be T'
T' - m * g = m * a
T' = 53 * ( 9.81 + 0.071) N
T' = 523.6 N
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