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ogbeide (co8876)-HWH Ch5+6 Frictional Gravitational Forces-storr-(37570) 1 This

ID: 1659072 • Letter: O

Question

ogbeide (co8876)-HWH Ch5+6 Frictional Gravitational Forces-storr-(37570) 1 This print-out should have 23 questions Multiple-choice questions may continue orn the next column or before answering. page-find all choices 1. T.en-2tGsin2 001 (part 1 of 2) 10.0 points he ceil. A small metal ball is suspended from ing by a thread of negligible mass. The ball is then set in motion in a horizontal circle so that the thread's trajectory describes a cone. 3. T-ria- The acceleration of gravity is 9.8 m/s What is the speed of the ball when it is in circular motion? Answer in terms of g, E and -=rvege 003 10.0 points In a hydrogen atom, the electron in orbit around the proton feels an attractive force of about 8.41 x 10N If the radius of the orbit is 4.8 x 10m, what is the frequency Answer in units of rev/s 004 (part 1 of 3) 10.0 points An early major objection to the idea that Earth is spinning on its axis was that Earth would turn so fast at the equator that people would be thrown into space. 7. u = sin Given: Pearth -6.37 x 10m murt.-5.98 × 1024 kg, r-= 1.74 x ids m , and 9-9.8 m/s 002 (part 2 of 2) 10.0 points How long does it take Twriad for the ball to Show the error in this logic by calculating rotate once around the axis? the speed of a 98.4 kg person at the equator ogbeide (o8876)-Hw #4Ch5+6, Frictional-Gravitational Forces-stom-(37570) Answer in units of m/s 2

Explanation / Answer

001.

in vertical, Fnet = T cos(theta) - m g = 0

T cos(theta) = m g ...... (i)


In horizontal, Fnet = T sin(theta) = m a_c

T sin(theta) = m v^2 / r

and r = L sin(theta)

T sin(theta) = m v^2 / L sin(theta) .... (ii)

(ii)/(i)

tan(theta) = v^2 / g L sin(theta)

v = sqrt[g L tan(theta) sin(theta)]

Ans: (2)

002. T = 2 pi r / v

T = 2pi L sin(theta) / sqrt[g L tan(theta) sin(theta)]

T = 2 pi sqrt(L sin(theta) / g tan(theta) )

T = 2 pi sqrt(L cos(theta) / g)


Ans: (7)

003. F= m w^2 r

8.41 x 10^-8 = (9.109 x 10^-31) w^2 (4.8 x 10^-11)

w = 4.386 x 10^16 rad/s

f = w / 2pi = 6.98 x 10^15 rev/s