1 of 1 Complete his worksheet along with the data ana na hom te l ratn utions tu

Question

1 of 1 Complete his worksheet along with the data ana na hom te l ratn utions turn botn at start of rest week's lab period The velocity lv) vesus tme graph is a sloped straight line This means that the slope is 8) decreasing C) constant Nobce that for this expermere, thie positon ¢x) versus nine et)graph es parabok, wNt the vebeity ev) versus time gragh is a sloped sta ght line. How do you espect the graph of the acpeleration a)ss sime to lookThe correct arswer to the previbus question is a clue 12710 You are given the same experimental t-up as the instructions, and told to add anextraman of &Dx10; step 5Theoretically, what wll the acceler ation be(Assume the acceler ation due togaity. dont forget significant digits

Explanation / Answer

If Velocity vs. Time is a sloped straight line that means it is making an angle with the x-axis. If there is slope that means velocity is constantly increasing with time. ==> there is acceleration. The slope is the acceleration which dv/dt. When we say it is a straight line, the slope at any point on the straight line will be constant. This implies that the acceleration is constant.

Answer: Constant slope [C]

(2)

x is parabola with respect to time. that means we have a quadratic term in position coordinate. the velocity would be a derivative of that which will be linear term and acceleration is going to be a derivative of velocity which would just be a constant. This scenario implies that the acceleration would be a constant. just like the slope of the a striaght line.

If we are given an extra mass then the force would be mg in addition to ma. both terms would add to give net force which we have to equate to get the force.

the last question is not clearly visible in the figure.

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