Whilst traipsing through the borogoves, with gorillas hurtling past you at five

Question

Whilst traipsing through the borogoves, with gorillas hurtling past you at five times the speed of sound, you discover a flask submerged in ice water (0.000°C). You quickly determine that the volume of the flask is 1000.0cm^3 but are uncertain of its material. Filling the flask with all the mercury that you have ( 991ml at a temperature of 0.000°C), you warm the flask and Mercury evenly until the mercury just starts to overflow, which happens at a temperature of 67.0°C. What is the coefficient of volumetric expansion for the unknown material? For mercury, beta=1.80×10^-4 (°C)^-1.

5. (20 pts) Whilst traipsing through the borogoves, with gorillas hurtling past you at five times ickly the speed of sound, you discover a flask submerged in ice water (0.000 °C). You qu determine that the volume of the flask is 1000.0 cm3 but are uncertain of its material. Filling the flask with all of the mercury that you have (991 ml at a temperature of 0.000°C), you warm the flask and mercury evenly until the mercury just starts to overflow, which happens at a temperature of 67.0°C. What is the coefficient of volume expansion for the unknown material? For mercury, = 1.80 x 10-4(°C)-1.

Explanation / Answer

coefficient of real expansion of the mercury = coefficient of apparent expansion of mercury + coefficient of volume exapnsion of flask

coefficient of apparent expansion of mercury = change in volume/(initial volume*temp difference)

coefficient of apparent expansion of mercury = (1000-991)/(991*67) = 1.35*10^-4

coefficient of volume exapnsion of flask = 1.8*10^-4 - 1.35*10^-4 = 4.5*10^-5 (oc)-1

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