Write a short one page letter to your classmate explaining why his response is i

Question

Write a short one page letter to your classmate explaining why his response is incorrrect and help him to come to a correct understanding of the motion that the figure represents.

( pts] Your is are be realistic Name OUESTION EXAM 1: WRITING due Wednesday September 27) At clear asked to write a short story describing the motion of a real object for which the response to position-versus-time graph. One of your classmates gives the following incorrect . "A guy is standing on top of a clientjumps off the cliff into , the a lakeHe swims across the lake and gets out on the other side." incorrect and help him ite a shortone-page letter to your classmate explaining why his response is to come to a correct understanding of the motion that the figure represents. x (mi) 30 10 Io Rubric Rpetent Emergent (pl Proficient B pts) He and relevant u scs and Uses physics Content Development way that substance of the letter ideas confused, conged. concepts in a understanding of Correct or uses straightforward ( otas & Mechanics Uses language and language of grammarpunctuation, punctuation that sometime vocabular: global the reader calling impedes errors in usage. Acture and formation ane Uses appropriate and relevant physics concepts to illustrate mastery of the material, conveying understanding and and are shaping the entire letter. Uses graceful language and punctuation that skillfully aning because of that generate meaning to connection communicates meaning to on the readers with clarity and tuency that is error free. phe letter is unit The letter is novel and Language has a few errors. The is ordinary or The letter lity budgement of the letter mundane . engaging

Explanation / Answer

The person was initially at 30 miles from origin (a reference point). He spent there for 1 hour. Then he began to go towards origin at a certain velocity.
velocity = (30 - 10) / (1 - 2) = - 40 mi/h   (the direction indicates that he traveled in opposite direction)
He took 1 hour traveling at 40 mi/h to reach 10 mile at the opposite side of the origin.
From there, he started accelerating towards origin
Initial velocity, u = -40 mi/h
Time taken, t = 3 h.
Distance traveled, s = 10 mi.
Using the formula, s = ut + 1/2 at2,
10 = - 40 x 3 + 0.5 x a x 32
9a = 260
a = 28.89 mi/h2.
So, in the final step, he accelerated back to the origin with in 3 hours with an acceleration of 28.89 miles/h2.

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