Guide for non-golfers: the tee is where the ball is launched from, and the green

Question

Guide for non-golfers: the tee is where the ball is launched from, and the green is where the golfer wants the ball to land. The green has a hole in it, and the golfer is trying to get the ball to go into the hole The golfer Inbee Park is at the tee at the 16th hole, a short par 3. The tee is 11.0 m vertically above the level of the green, and some distance horizontally from the hole. Park grabs her 5-iron, and strikes the ball so that it is launched from the tee with an initial velocity of 42.0 m/s at an angle of 39.0° above the horizontal. The ball lands on the green at a distance of 5.00 m from the hole, and then, still moving away from the tee, bounces twice, and then rolls right into the hole. The crowd goes crazy-it's a hole in one! Neglect air resistance, and assume that the acceleration due to gravity is 9.80 m/s2 (a) How long does the ball spend in the air? (The time it leaves the tee until it first lands on the green.) Assume the green is perfectly horizontal (b) What is the horizontal distance from the tee to the hole?

Explanation / Answer

Given h = 11 m

velocity v0 = 42 m/s

angle theta = 39

a) we have the equation

s = (u * t) + (1/2 * a * t^2)

here it is the ball projected from a height at an angle so

h = (-voy * t) + (1/2 * g * t^2)

h = (-vo * sin(theta) * t) + (1/2 * g * t^2)

11 = - (42 * sin(39) * t) + (1/2 * 9.8 * t^2)

t = 5.78 s

this is the time it leaves the tee until it first lands on the green

b) the horizontal distance where it first lands on the green is

x = v0 * cos(theta) * t

x = 42 * cos(39) * 5.78

x = 188.66 m

the total horizontal distance is 188.66 + 5

193.66 m

Related Questions

Navigate

• Browse (All)
• Browse G
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.