2. Instead of releasing the ball from rest imagine throwing the ball down to the

Question

2. Instead of releasing the ball from rest imagine throwing the ball down to the floor. Once the ball is free of your hand will your experimental value of g change? If so, will it be larger or smaller?

3. The path of an object falling due to gravity is a downwards opening parabola. In the position vs. time graph, the parabolic sections open upward instead. Explain why.

4. What is physically happening at the sharp tips of the position vs. time graph? At those moments, is the ball still in free fall? Explain why or why not.

5. Are there moments when the ball's velocity is zero? Where are they on the position vs. time graph? Is the ball still in free fall at those moments? Explain why or why not.

6. Is it possible for the ball's velocity and acceleration point in different directions? Describe in your graph of position vs. time when this would occur. (Hint: Is the slope of the tangent line to the curve positive or negative?)

Please help me with these questions about this lab!

Thank you.

Free Fall.cap* File Edt Workbook Display Journal Help wage #1 Tools x Displays X Graph 0.8 Run #25 Quadratic A = 4.89 ±0.011 | B =-34.6 ± 0.077 c=61.4 ±0.14 RM SE = 0 .00 1 30 8 04 0.0 mt b m= 9.78 ±0.033 b =-34.6 ± 0.12 Curva Fit Run #25 | H 1.000 Text Box Tuxt Entry Box 0.0 0.5 1.0 1.5 2.5 3.0 4.0 4.5 5.0 5.5 6.0 6.5 7.0 7.5 8.0 Time (s) 00:05.15 Motion Sens or 20.00 1:01 PM

Explanation / Answer

1) The value of g will be same.

Once the ball is released, it is under free fall. The only force acting on it is the force of gravity. The value of acceleration due to gravity is constant. So, value of g remains same.

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